sn=(n(t1+tn))/2
- n is term number
- t1 is first term
- d is what you add
- tn is term number in the sequence
tn=t'∙r^(n-1) (geometric)
sn=(t1(1-r^n))/1-r
- r is what you multiply by
lim/n infinity
- if the degree of the top is equal to the degree of the bottom then the answer is the coefficient
- if the degree of the top is greater than the degree of the bottom the answer is infinity
- if the degree of the top is less than the degree of the bottom the answer is 0
- if the rules don't apply, use your calculator
for geometric sequences if the absolute value of r is less than 1 then it goes to 0
the sum of infinite series can only be found when a geometric sequence where the absolute value of r is less than 1
s=t1/1-r
- if the absolute value of r is not less than 1, the series diverges (doesn't approach a number)
- if the absolute value of r is less than 1, the series approaches a number
Formula: S = t1/1-r
ReplyDelete*can only be found when a geometric sequence where |r|<1
*if |r| is not less than 1 we say the series diveges - doesn't approach a #
* if |r|<1 then we say the series approaches a #
Examples:
1. Find the sum of the infinite series: 9 - 6 + 4
(geometric)
r = -6/9 = -2
|-2/3| < 1
S = 9/(1 - (-2/3)) = 27/5