i'm going over old stuff, and for the most part, i remember everything. so i'm explaining how to complete the square.
when given an equation (ax^2+bx+c=0) where "c" is the constant, first add or subtract the constant over (ax^2+bx+_=-c). Second, divide the linear term (b) by two and then square it (b/2)^2. Your would then add your squared, lets call it "d", term to both sides of the equal sign (ax^2+bx+d=-c+d). You would then factor to get (ax+b/2)^2=-c+d. After factoring, you would take the square root of both sides (ax+b/2)=+/- √-c+d. Then, you would add or subtract (b/2) to both sides. And finally, you would divide by "a" to get "x" by itself. You would then write in coordinate form.
What I don't understand from the exam review is how to get an equation from INTEGRAL COEFFICIENTS!!!!! help.
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to solve for integral coefficients all you have to do is factor the given equation and the resulting X's will be your integral coefficients.
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