Brob said that while she is out since she is not able to teach anything new we can post information and questions from old chapters
someting i really understand from the past are
The steps for condensing logs
First you have to remember the relations
Mn = m+n
m/n = m-n
m^k = k log M
sub b B^k = k
b^log sub b^k = K
so any problem will fit into one of these relations
Ex: expand log sub b MN^2
Log sub b M + 2 Log sub b N
STILL....
What I do not understand is how to work is the solving for exponent part that includes
Sandwiching and flipping the fraction
For example
X^5 + X^-2 / X ^-3
So now I don’t understand how in my notes the next step is
X^2/X^2 times X^5 + 1/X \^3 times 1/1 all over 1/X^3
I really think I need the rules for flipping fractions and when to sandwich explained simply to me
Subscribe to:
Post Comments (Atom)
Exponents:
ReplyDelete1. b^x * b^y = b^x + y....example: 2^3 * 2^5 = 2^8
2. b^x/b^y = b^x - y....example: 5^7/5^4 = 5^3
3. (ab)^x = a^xb^x....example: (3 * 7)^3 = 3^3 * 7^3
4. (a/b)^x = a^x/b^x....example: (3/5)^3 = 3^3/5^3
5. (b^x)^y = b^xy....example: (2^2)^3 = 2^6
6. b^x/y = y^√b^x....examples: 5^3/4 = 3^√5^3
7. to solve for exponents:
write as the same base
set exponents equal
then solve for x
here are some examples:
(a). 5^3x = 5^7x - 2
In this first part we have the same base on both exponentials so there really isn’t much to do other than to set the two exponents equal to each other and solve for x.
3x = 7x - 2
2 = 4x
x = 1/2
So, if we were to plug x = 1/2 into the equation then we would get the same number on both sides of the equal sign.