So my Christmas holidays were pretty good. I went on the levee every night to have a fire with my friends, I had a fire during the day with Remi, and I helped people build bonfires on the levee. I still haven't gotten my Christmas present because my phone contract does not expire till January 6th. I can't lie though, I forgot how to do a good bit of things in math, but I do remember one thing. I remember how to solve for x in a log.
1. log5 25 = x
The 5 would be the number raised to an exponent. The x would be the exponent, and 10 would be what 5 raised to the exponent equals. So it should look like this:
5^x = 25
x would equal 2
there is alot more to solving logs
ReplyDeleteand they are easy to remember
there is logs properties..
logb MN = logb M + logb N
logb M/N = logb M - logb N
logb M^K = K logb M
logb b^k = k
b^logb^k = k
& theres
Changing Bases: (Done when you can't solve a log)
Rewrite it as an exponential
Take the log of both sides
Move the variable to the front
then solve
Example:
log5 10 = x
5^x = 10
log 5^x = log 10
x log 5 = 1
x = 1/log 5