Reflection 3

In this reflection I will help explain how to solve trig equations with any line in the equation.

For these equations you would use m = tanZ. Where as m would be the slope and Z would be the angle of inclination. If A would happen to equal C in the equation then the angle of inclination would always be pie over four.

An example of this problem would be to find the angle of 2X + 5Y = 15. For this equation m would be -2/5 which would make the equation tanZ = -2/5. You would then have to take the inverse of tan to make change it to Z = tan^-1(-2/5). The answer would come out to be 21.801 degrees. Since tan is positive in quadrant one and three it would be negative in quadrant two and four. So we would have to take 21.801 degrees, make it negative and add 180 degrees which then makes it 158.199 degrees. Now we take the 21.801 degrees and to change it to quadrant four so we make it negative and add 360 degrees which then comes out to 338.199 degrees. So therefore the answer would be Z = 158.199 degrees, and 338.199 degrees.