Okay so this week we had a quiz on 9-1 which was all word problems. I did not do well on it at all. I guess word problems are just not my thing. I could use some help with problems like on our homework worksheet (ch. 9 quiz). I do not understand how to set up the ones that do not give you any angles. If anyone can help me with this it would help me out tremendously. Lets review some trigonometry.
--The hypotenuse is opposite the right angle.
--A= 1/2 bh
SOHCAHTOA---stands for....
Sin θ= opposite leg/hypotenuse
Cos θ= adjacent leg/hypotenuse
Tan θ= opposite leg/adjacent leg
--To find the area of a non right triangle use this formula:
--A= 1/2 (leg)(leg)SIN(angle b/w)
--When you have a non right triangle that has pairs, use the law of sines.
Sin A/a = Sin B/b= Sin C/c
All you are doing is setting up a proportion.
**Remember to solve for an angle, you have to take the inverse.
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okay so im going to comment on my own question :)
ReplyDeleteWhen solving a triangle with no angles, you would use the law of cosines. I was confused because we had not learned it yet but we did today so that answered my question.
when you cannot use the law of sines, use the law of cosines. always pick the law of cosines last because it is the most time consuming on a test or ACT.
Law of Cosines
(opp leg)^2= (adj leg)^2 + (other adj leg)^2 -2(adj leg)(adj leg) Cos(angle b/w)
use an angle to orient yourself like SOHCAHTOA!!