All right
this week can be described in many ways.
stressful. overwhelming. etc
First lets talk about the takehome test.
that test was still freaking hard. This bothers me so badly.
even with the notes infront of my im thrown off by tests. Im back to the drawing board on trying to figure out why.
Then came the study guides in need of completion. i was happy to see that for the majority of the tests i could still answer the same ones i did the day i took the actual tests. This boosted my confidence for the coming exam
there were however still a few questions i cannot find notes to answer the following questions
chapter 1 question number 19: find the perpendicular bisector of the line 4x-2y=4 through the point (1,0)
I need to know the equations of slope intercept, point slope, and standard form
what is the degree of a line
Chapter 4 number 5 letter d
is y=squareroot 9-x^2 symmetric about the line y=x
chapter 5 number 3 letter f
find the exact value of -ln e
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the natural log of e is 1.
ReplyDeletee is the opposite of ln
so when you have -ln e
it is equal to ln/e=1..
alrighty well i can help with the equations you are having trouble with.
ReplyDeletethe equation for point-slope is
y-y1= m(x-x1)
the equation for slope intercept is
ax+by=c
and the standard form equation is
y= mx+b
hope it helped!! :)
chapter 1 #19:
ReplyDelete4x-2y = 4
(solve for y)
-2y = -4x + 4
(divide by -2)
y = 2x - 2
(m=2, perpendicular slope=-1/2)
y - y1 = m(x-x1)
y - 4 = -1/2(x-1)--answer
Chapter 4 #5d:
y = squareroot 9-x^2
(x)^2 = (squareroot 9-x^2)^2
x^2 = 9 - y^2
y^2 = 9 - x^2
y = squareroot 9-x^2
(the answer is yes because you get the same exact equation you started with..)