Sunday, October 11, 2009

Stephanie's Reflection

I have had many problems with the study guide this week, especially with Chapter 5 but I'll start at the beginning.

Chapter 1:
#13 - y=x+2; y=x^2+6x+8 Set them equal. x+2=x^2+6x+8
Then what? Solve for x? How do I get the answers B-Rob gave us if I do so?

Chapter 2:
#4 - The equation x^4+x^3-5x^2+x-6 has the roots x=2 and x=-3. Find the remaining roots.
Um, what? I looked it up in my book and notes but apparently can't seem to find anything on this.
#8 - Solve for x: 2x^3-5x^2-4X+3
How to get the answers she gave us, I have no idea. I tried many ways and am still baffled.
#9 - Solve for x: x^4-7x^2-8
Same as #8, I have no idea.


Chapter 3:
#4 - The equation x^4-2x^3-4x^2+2x+3 has the x-intercepts x=-1 and x=3. Find the remaining x-intercepts.
#8 - which is the same as the #8 of the previous chapter.
#9 - Solve for x: 2x^4+14x+12
#11 - Solve for x: x^3+14x^2+56x+64
#16 - Solve for x: (x+3)/8+(x-1)/4 is less than or equal to 3x/6

Chapter 4:
#3/C - Domain and range of y=(4x-3)/(7x+1)
#3/D - Domain and range of y= square root of(x-4)+3


Chapter 5:
#2 - Express y in terms of x: log(2y)=3log(x)+log(x-1)
#3/B - 2^(log 2 of 6)
#3/D - log 5 of 10
#4 - 2^x=100
#13 - 9^(x+2)=1/729
#15 - Solve for x: 3^(2x)+5(3^x)+6

5 comments:

  1. #13:y=x+2; y=x^2+6x+8

    x+2=x^2+6x+8

    move everything to one side & + or - like terms

    x^2 + 5x + 6 = 0

    factor

    (x + 3) (x + 2) = 0

    set equal to zero

    x = -3 x = -2

    plug back into one of the equations

    y = x + 2
    y = -3 + 2
    y = 1

    y = x + 2
    y = -2 + 2
    y = 0

    your points:
    (-3,-1) (-2,0)

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  3. Chapter 2:

    #8: rational root theorem (-1 & 3 works)

    #9: x^4 - 7x^2 - 8

    g = x^2
    g^2 - 7g - 8
    g^2 - 8g + g - 8
    g(g - 8) + 1(g - 8)
    (g+1) (g-8)

    x^2 + 1 = 0
    x^2 = -1
    x = +/- i

    x^2 - 8 = 0
    x^2 = 8
    x = +/- 2sqrt2

    (i,0) (-i,0) (2sqrt2, 0) (-2sqrt2, 0)

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  5. chapter 3:

    #4, #8, #9, & #11: rational root theorem works for all of them

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