Alrighty well I am having such a difficult time studying for this exam. I have basically accepted the fact that I am going to fail :(
Parabolas have no major axis and no asymptotes.
Axis of symmetry x=-b/2a
Finding the vertex
(-b/2a, f(-b/2a))
or
complete the square to get vertex form
y=(x+a)^2+b a&b are #'s
(-a,b) vertex
focus: 1/4p= coeff of x^2 then add p.
directrix is p units behind vertex. subtract p.
EX: 1/8y^2
v(0,0)
Focus: p=2
(2,0)
directrix: x=-2
Sunday, October 11, 2009
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment