This week was an okay week for me. When we got tests back I was excited to see that my grades have started t o improve, not that I was making bad grades but A’s are better than B’s. Let’s see, Chapter 5 I feel like I get most of it I definitely know how to work logs. Of course solving logs are my favorite because they are a matter of switching around what is already given to you. Changing bases really isn’t hard either. Condensing logs isn’t hard for me to grasp, even when there are awkward symbols and to be honest; I really appreciate Mrs. Robinson explaining that the symbols mean nothing concerning the solving of the problems. I know that’s mostly a common sense thing but I know it would have tripped me up on the ACT.
The steps for condensing logs are easy
First you have to remember the relations
Mn = m+n
m/n = m-n
m^k = k log M
sub b B^k = k
b^log sub b^k = K
so any problem will fit into one of these relations
Ex: expand log sub b MN^2
Log sub b M + 2 Log sub b N
What I do not understand is how to work is still the solving for exponent part that includes
Sandwiching and flipping the fraction
For example
X^5 + X^-2 / X ^-3
So now I don’t understand how in my notes the next step is
X^2/X^2 times X^5 + 1/X \^3 times 1/1 all over 1/X^3
I really think I need the rules for flipping fractions and when to sandwich explained simply to me
Any help though would be great!
Sunday, September 27, 2009
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I think I understand what you are asking about the sandwhich stuff.
ReplyDeletewhen you sandwhich, your problem will usually have reduced to X^-2/X^-3
from there, you would flip both of them to get (1/X^2)/(1/X^3)
then you would multiply the two outside (1*X^3) to get your numerator and the two inside (1*X^2) to get your denominator.
Finally, you would just simplify.