This week has been pretty easy for me. We got to logs and we did some exponent thing. Im really happy that we got to logs because im really good at it. When solving logs, you have to put the log in the form b^a=x. This is exponential form
Ex: log(2)4=x
Put the log in the form b^a=x. So it would look like 2^x=4
Then you see how many times the 2 can go into the 4 which is 2 times so your answer will be x=2.
We also learned how to put it into log form. All you have to do is do the exponential form backwards starting with b^a=x.
Ex: 3^x=6
The 3 will be ur subscript, the x will be what ur log equals and the 6 will be the number infront of the log. It will look like log(3)6=x.
What i dont understand is the exponent things we did. I just cant understand it. But when i really get confused is when you have to do the "sandwich" thing and you have a fraction over a fraction. I dont understand how to get it in that form so if anyone can help me with that, I'd be grateful
Subscribe to:
Post Comments (Atom)
This comment has been removed by the author.
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteAlrighty well to be honest with you, im not too sure im to one to answer many questions about the exponents. im kinda having trouble with them myself but i do understand the sandwich thing so maybe i can help a little.
ReplyDeleteexample: x^7+1 / x^2 // 1/ x^3
sorry thats the best way i can
1 make a fraction sandwich haha.
okay so sandwich... multiply the two buns so you would multiply x^7+1 times x^3. then multipy the middle terms which is x^2 and 1.
you would get.. x^3(x^7+1) / x^2 // x(x^7+1)
distribute.... and your answer would be x^8+x
Exponents:
ReplyDelete1. b^x * b^y = b^x + y....example: 2^3 * 2^5 = 2^8 (when mulitpling you dd the exponents)
2. b^x/b^y = b^x - y....example: 5^7/5^4 = 5^3
(when dividing you subtract the exponents)
3. (ab)^x = a^xb^x....example: (3 * 7)^3 = 3^3 * 7^3 (here you would raise to whatever power)
4. (a/b)^x = a^x/b^x....example: (3/5)^3 = 3^3/5^3 (would do the as #3)
5. (b^x)^y = b^xy....example: (2^2)^3 = 2^6
(mulitply the exponents)
6. b^x/y = y^√b^x....examples: 5^3/2 = 2^√5^3
(like in this problem is divided by 2 so u would take the square root..if it was divied by 3 u would the cube root & so on..)
7. to solve for exponents:
write as the same base
set exponents equal
then solve for x
here are some examples:
(a). 5^2x = 5^6x - 2
In this first part we have the same base on both exponentials so there really isn’t much to do other than to set the two exponents equal to each other and solve for x.
2x = 6x - 2
2 = 4x
x = 1/2
So, if we were to plug x = 1/2 into the equation then we would get the same number on both sides of the equal sign.
hope that somewhat helps..