Ok so this week, I was kinda relieved. We didn't have a test this week so im kinda happy about that mainly cause I need some help finding domain and range. What I understand is finding reflections. Its really simple cause all you have to do is get an answer that matches the original equation. When finding reflections, you have to follow some steps:
To reflect the x-axis, you put a negative infront of the equation
To reflect on y-axis, you plug in (-x).
To reflect on y=x, find the inverse:
a. switch x & y
b. solve for y
and to reflect on the origin, reflect the y and x axis again.
Some of the things i dont understand is working f(x) stuff. I understand it when we learn it that day and then after that it just ends. I dont know how to set up the problems. So if someone could help me with (f o g)(x) and stuff like that, i would be grateful
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(f o g)(x) is pretty easy. Just change the notation to f(g(x)) to make it simpler to understand. Then you work from the inside out. Say f(x)=x+5 and g(x)=3x+2. If you want to find (f o g)(x), first you work from the inside then out.You take g(x) and plug into F(x)
ReplyDeleteSo it should look like this f(3x+2). Plug in 3x+2 for x in f(x).
(f o g)(x)=(3x+2)+5
simplify to get:3x+7
Hope that helped.
When adding, subtracting, multiplying, or dividing functions, all you have to do is break up the problem. For instance, (f+g)(x)= add f(x)+g(x).
ReplyDeleteexample: f(x)=x+1 g(x)=x^2+x-2
you would set it up like this....
(f+g)(x)= x+1+x^2-3= x^2+x-2
same thing applys with subtraction, multiplication, and division.
When you see (fog)(x) you break it up a little differently.
since the f is first, you would do f(g(x))
example: same #'s from the first example.
(fog)(x)=f(g(x))= x^2-3+1= x^2-2
Hope it helped! good luck on tomorrows test