This week went by pretty fast, probably because I was only there three days. We did a lot of domain and range when Mrs. Robinson was out. Thursday we went over functions and reflections. I don't really know what we did Friday. I guess it might be good to figure that out. I'm not really too confident with reflections. Really, I just need to memorize the formulas for that. I do know how to work the functions, though. For example:
(f-g)(x) is f(x)-g(x)
If f(x)= 2x-1 and g(x)=3x then we get 2x-1-3x= -x-1
(f+g)(x)= 2x-1+3x= 5x+1
(f o g)(x)- this just means f(g(x))
So if f(x)=x+2 and g(x)= 4x+1 then we get (f o g)(x)= (4x+1)+2= 4x+3
In this case the answer would be 4x+3.
Once again, I'm not really sure about reflections. Also, I don't know what we went over Friday. So any help would be appreciated.
(f-g)(x) is f(x)-g(x)
If f(x)= 2x-1 and g(x)=3x then we get 2x-1-3x= -x-1
(f+g)(x)= 2x-1+3x= 5x+1
(f o g)(x)- this just means f(g(x))
So if f(x)=x+2 and g(x)= 4x+1 then we get (f o g)(x)= (4x+1)+2= 4x+3
In this case the answer would be 4x+3.
Once again, I'm not really sure about reflections. Also, I don't know what we went over Friday. So any help would be appreciated.
Reflection Steps:
ReplyDelete1. to reflect on the x - axis put a negative in front of the equation
2. to refelct on the y - axis plug in (-x) into the equation
3. to reflect on y = x find the inverse..first switch x and y..then solve for y
4. to reflect on the orgins do steps 1 & 2
*it is symmetric if you get the same thing you had before you reflected
Example: y = x^2
1. x - axis
y = -x^2 (reflection; not symmetric)
2. y - axis
y = (-x)^2
y = x^2 (reflection; is symmetric)
3. y = x
x = y^2
y = √x ( reflection; not symmetric)
4. orgin
y = -(-x)^2
y = -x^2 (reflection; not symmetric)
Helpful hints:
*if your equation has xs & ys to check the x - axis plug in (-y) and for the orgin plug in (-x) & (-y).