Okay so this week was pretty good for me. I really understand logarithms so I will try to explain them as best as I can.....
the basic formula is log b^x=a
this is how you solve b^a=x
All you do is switch your a and x term. the base b does not change, only the a and x term.
example: log 5^25=2
5^2=25
example: if your problem does not have a term on the other side of the = sign, add x
log 2^8 =x
2^x=8 ****when the directions ask for exponential form, this is your answer
x=3 ****this is your answer if the directions say solve. always solve for x.
REMINDER : logs are implied to have a base of 10. if there is no base, it is understood to be 10.
Okay I hope that helped. I am having difficulty with the exponent problems. if anyone could help me with problems like # 17-28 on page 178 it would help me greatly!!! thanksss :)
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