Sunday, August 30, 2009

Reflection #2??????

OK so I'm not so sure on weather or not our class is suppose to do the reflection or not but I saw that a bunch of people in the other class has done them so I guess I will too. Well this week started off pretty good. I understood everything we did and even had to teacher it to some of the other kids in the fourth hour class in our study group. Once again I forgot how to do everything when I got the test, but this time it was different. Towards the last few minutes of the class I started remembering everything again and got a little bit done on the test.
Now to the math, one thing I really under stood was factoring by grouping. Say you have x^3+3x^2+4x+12. First, you would separate the problem into two parts by using parenthesis and you would get (x^3+3x^2)+(4x+12). Next you reduce the problem and you'd get x^2(x+3)+4(x+3). After that you group the front two together and the parenthesis, you get (x^2+4) and (x+3). You get (-3,0) as your answer from (x+3). To find the answer to (x^2+4) you get x^2=-4 then square it and you get x=+or-2. Your answers would be (-3,0) (2,0) (-2,0).
The one thing I had trouble with was the rational root theorem. It's a lot of steps and when I had to do it on the test I didn't know where to start. I just skipped the whole thing.

2 comments:

  1. okayyy, i can help with the rational root theorem! :) so basically knowing the steps is the first thing that you need to master to understand it.
    1. find all the rational roots
    P is going to the the factors of the constant and Q is going to be the leading coefficient
    2. list out all the possible roots and add a +
    -
    in front of each root. then put your P's over Q's
    3. plug in your eguation into the Y=.... and hit 2nd graph to find which roots give you remainder of 0.
    4. after you find your root that equals 0, plug it in the box for synthetic division. when you get your answer, it has to be a quadratic. If it is not, then you know you have to do synthetic divison again. use the equation from the answer of your first synthetic division problem, not the original problem. once your answer is a quadratic, you still must simplify because your answer has to be points. SO take your quadratic and do quadratic formula and theres your answer!!!

    Hope it helped :)

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